42. 连续子数组的最大和

#Algorithm

NowCoder

题目描述

{6, -3, -2, 7, -15, 1, 2, 2}，连续子数组的最大和为 8（从第 0 个开始，到第 3 个为止）。

解题思路

public int FindGreatestSumOfSubArray(int[] nums) {
    if (nums == null || nums.length == 0)
        return 0;
    int greatestSum = Integer.MIN_VALUE;
    int sum = 0;
    for (int val : nums) {
        sum = sum <= 0 ? val : sum + val;
        greatestSum = Math.max(greatestSum, sum);
    }
    return greatestSum;
}